Question

# The density of ice is $$917 \ kg/m^3$$. the friction of the volume of a piece of ice will be above water when floating in fresh water is:-

A
0.083
B
0.042
C
0.412
D
0.813

Solution

## The correct option is A $$0.083$$$$f\times v\times 1000\times9.8=(1-f)\times V\times917\times9.8$$ This gives $$f=\dfrac{917}{1000}$$ =0.917The fraction of block above water$$1-.917$$$$= 0.083$$Physics

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