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Question

The density of ice is $$917 \ kg/m^3$$. the friction of the volume of a piece of ice will be above water when floating in fresh water is:-


A
0.083
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B
0.042
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C
0.412
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D
0.813
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Solution

The correct option is A $$0.083$$
$$f\times v\times 1000\times9.8=(1-f)\times V\times917\times9.8$$ 
This gives $$f=\dfrac{917}{1000}$$ =0.917
The fraction of block above water$$1-.917$$
$$= 0.083$$

Physics

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