The diagonal from B to D is drawn in parallelogram ABCD. Which of the following methods can NOT be used to prove $Δ D A B ≅ Δ B C D$ ?

SSS

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SAS

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SSA

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ASA

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Solution

The correct option is C
SSA

SSA is not a congruence condition. So, it can not be used to prove congruency, all the other conditions can be.

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△ D A B ≅ △ B C D

In parallelogram ABCD, AP and CQ are perpendicular to diagonal BD.
It can be proved that $Δ$ APB $≅$ $Δ$ CQD.

In $△ A B C$ and $△ X Y Z$ , if BC = YZ, $∠ A B C = ∠ X Y Z$ and $∠ A C B = ∠ X Z Y,$ , then by which postulate is $△ A B C ≅ △ Z X Y$ ?

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