The diagram shows a rhombus of sides $13$ cm. PTR and QTS are straight lines and TR= $5$ cm.
Which among the points A, B, C and D is equidistant from PQ and QR but less than $12$ cm from Q?

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Solution

In the rhombus $P Q R S,$
$\Rightarrow Q R = 13 c m,$ $T R = 5 c m$
$∴ Q T = 12 c m$
( Pythagoras theorem )
Both A and C are equidistant from $P Q$ and $Q R$ but only A is less than $12 c m$ from $Q .$
Hence, the answer is solved.

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The diagram shows a rhombus of sides 13 cm. PTR and QTS are straight lines and TR=5 cm. Which among the points A, B, C and D is equidistant from PQ and QR but less than 12 cm from Q?

In the rhombus PQRS,⇒QR=13cm, TR=5cm∴QT=12cm ( Pythagoras theorem )Both A and C are equidistant from PQ and QR but only A is less than 12cm from Q.Hence, the answer is solved.

The diagram shows a rhombus of sides $13$ cm. PTR and QTS are straight lines and TR= $5$ cm.
Which among the points A, B, C and D is equidistant from PQ and QR but less than $12$ cm from Q?

In the rhombus $P Q R S,$
$\Rightarrow Q R = 13 c m,$ $T R = 5 c m$
$∴ Q T = 12 c m$
( Pythagoras theorem )
Both A and C are equidistant from $P Q$ and $Q R$ but only A is less than $12 c m$ from $Q .$
Hence, the answer is solved.