Question

The diagram shows two test-tubes $A$ and $B$. Test-tube $A$ contains a green water plant. Test-tube $B$ contains both a green water plant and a snail. Both Test-tubes are kept in sunlight. Answer the question that follows.
$\left(i\right)$ Name the physiological process that releases the bubbles of oxygen.
$\left(ii\right)$ Explain the physiological process as mentioned above in $\left(i\right)$.
$\left(iii\right)$ What is the purpose of keeping a snail in test-tube $B$?
$\left(iv\right)$ Why does test-tube $B$ have more bubbles of oxygen?
$\left(v\right)$ Given an example of a water plant that can be used in the above experiment.
$\left(vi\right)$ Write the overall chemical equation for the above process.

Answer 1

$\left(i\right)$ In the given experiment, bubbles of oxygen are released due to the process of light reaction of photosynthesis.
$\left(ii\right)$ Photosynthesis is a process in which green plants (plant cells having chlorophyll) take in carbon-dioxide and water in presence of sunlight to produce glucose. It releases oxygen gas during the photolysis of water which is a part of the light reaction.
$\left(iii\right)$ The purpose of keeping the snail in the test tube B is the production of carbon dioxide which is used by the plant.
$\left(iv\right)$ Test tube B have more bubbles of oxygen because the rate of photosynthesis is more in test tube $B$ as it gets more ${CO}_2$ from the snail.
$\left(v\right)$ Hydrilla is a water plant which is used for such experiments.
$\left(vi\right)$ $6{CO}_2+12H_{2}O\underset{chlorophyll}{\overset{light}{\to }}{C}_6{H}_{12}{O}_6+6H_{2}O+6O_2\uparrow$