The differential equation of family of parobalas with foci at the origin and axis along the X- axis, is
y(dydx)2+2xdydx−y=0
Let the directrix be x=−2a and latus rectum be 4a then the equation of the parabola is (distance from focus = distance from directrix).
x2+y2=(2a+x)2⇒y2=4a(a+x)
On differentiating w.r.t. x, we get y.dydx−2a⇒a=y2dydx
On putting this value of a in eq. (i) the differental equation is
y2=2y=dydx(y2dydx+x)⇒y(dydx)2+2x(dydx)−y=0