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Question

The differential equation of the family of curves y=a cos(x+b) is

[MP PET 1993]


A

d2ydx2y=0

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B

d2ydx2+y=0

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C

d2ydx2+2y=0

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D

None of these

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Solution

The correct option is B

d2ydx2+y=0


Given equation y = a cos (x + b)
Differentiate it w.r.t x we get dydx=a sin (x+b)
Again d2ydx2=a cos (x+b)=y or d2ydx2+y=0.


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