CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The differential equation whose solution is Ax2+By2=1 where A and B are arbitrary constants, is of


A
first order and second degree
loader
B
first order and first degree
loader
C
second order and first degree
loader
D
second order and second degree
loader

Solution

The correct option is C second order and first degree
Differentiate the given equations for 2 times and eliminate A, B
Ax2+By2=1
Differentiating
2Ax+2Bydydx=0
Ax+By.dydx=0                  - (1)
Differentiating again
A+B[y.d2ydx2+(dydx)2]=0            - (2)
On solving (1) & (2); we will get values of A and B in terms of dydx,d2ydx2 & (dydx)2 and we insert those values in the given expression.
Hence order = 2
Degree = 1

Co-Curriculars

Suggest Corrections
thumbs-up
 
1


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image