wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The differential equation xdydx=5y(lnxlny) is:

A
a homogeneous but not linear differential equation.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
a linear but not homogeneous differential equation.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
both homogenous and linear differential equation.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
neither homogenous nor linear differential equation.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A a homogeneous but not linear differential equation.
Given,Differential equation as xdydx=5y×ln(xy)
dydx=5(yx)ln(xy)
Let f(x,y)=dydx
f(x,y)=5(yx)ln(xy)
For f(x,y) to be homogenous,f(kx,ky)=knf(x,y) (where n is its order)
Consider,f(kx,ky)=5(kykx)ln(kxky)=5(yx)ln(xy)=f(x,y)
The given equation is homogenous equation.

Consider given Differential equation, xdydx=5y×(lnxlny)
xdydx=5y×lnx5y×lny
For equation to be linear,
a)The powers of dependent variable and its derivative to be power of one.
b)The coefficient of dependent variable should be either function of independent variable or constant.
Since in our equation the co-efficient (for the term -5ylny) term is not function of x.The given equation is non-linear.
Thegivenequationishomogeneousbutnonlinear

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon