The correct option is B 246
Let the digits of the three digitnumber be x, 2x, 3x.
So, the number is, (100×x)+(10×2x)+3x=123x
After interchaning the units digit andthe hundreds digit, the number becomes (100×3x)+(10×2x)+x=321x.
When the units digit and the hundreds digit are interchanged with each other, we get 321x−123x=396⇒198x=396⇒x=396198⇒x=2
Therefore, the digits are x=2,2x=4 and 3x=6
Thus, the number =123x=123×2=246.