Question

The discriminant of the given quadratic equation is -a then find a.
$x^2+x+1=0$

Answer 1

$\Rightarrow$ Given quadratic equation is $x^2+x+1=0$

$\Rightarrow$ Here, $a=1,b=1,c=1$

$\Rightarrow$ $D=b^2-4ac$

$\Rightarrow$ $-a=(1{)}^2-4(1\left)\right(1)$

$\Rightarrow$ $-a=1-4$

$\Rightarrow$ $-a=-3$

$\therefore$ $a=3$