CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The displacement of a charge Q in the electric field E=e1^i+e2^j+e3^k is ^r=a^i+b^j. The work done is
  1. Q(ae1+be2)
  2. Q(ae1)2+(be2)2
  3. Q(e21+e22)(a+b)
  4. Q(e1+e2)a2+b2


Solution

The correct option is A Q(ae1+be2)
By using W=Q(E.Δr)
W=Q[(e1^i+e2^j+e3^k).(a^i+b^j)]=Q(e1a+e2b)

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image