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Question

The displacement of charge q in the electric field E=e1^i+e2^j+e3^j isr=a^i+b^j. The work done is

A
Q(e1+e2)a2+b2
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B
Q(a+b)e12+e22
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C
Q(ae1+be2)
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D
Q(ae1)2+(be2)2
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Solution

The correct option is C Q(ae1+be2)
F=QE

W=r.F

W=Qr.E

W=Q(e1^i+e2^j+e3^k).(a^i+b^j)

W=Q(ae1+be2)

Answer-(C)

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