Question

The displacement time graph for two particles A and B are straight lines inclined at angles of ${30}^o$ and ${60}^0$ with the time axis. The ratio of velocities of $V_A:V_B$ is

• A. $1:2$
• B. $1:\sqrt{3}$
• C. $\sqrt{3}:1$
• D. $1:3$

Answer 1

The correct option is D $1:3$

As velocity $v=\frac{dx}{dt}=slope$ of $x-t$ graph.

so $V_A:V_B=slop{e}_A:slop{e}_B=tan{30}^0:tan{60}^0=\frac{1}{\sqrt{3}}:\sqrt{3}=1:3$