Question

The displacement-time graph of a particle executing SHM is shown in the figure. Then

• A. the velocity is maximum at t=T/2
• B. the acceleration is maximum at t=T
• C. the force is zero at t=3T/4
• D. the potential energy equals the oscillation at t=T/2

Answer 1

Answer: (B), (C), (D)

the acceleration is maximum at t=T
the force is zero at t=3T/4
the potential energy equals the oscillation at t=T/2

From the graph, velocity is maximum at $t=0,T$
The acceleration ,$\frac{d^{2}y}{d{t}^2}$ is maximum at $t=T$
Force is zero at $t=T/2,3T/4$
As the interval of max and min displacement is $\frac{T}{2}$, so the potential energy equals the oscillation at T/2.