Question

The displacement x of a particle moving in one dimension is related to time t by the equation t=√x+3 where x is in metres and t in seconds. The displacement of the particle when its velocity is zero is

A

zero

B

4 m

C

1 m

D

0.5 m

Solution

The correct option is A zero Given that, t=√x+3 ⇒√x=t−3 Squaring both sides, x=t2−6t+9 Velocity, v=dxdt=2t−6 For velocity, v to be equal to zero, 2t−6=0⇒t=3 s At t = 3 s, displacement, x=t2−6t+9=32−6×3+9=0 Hence, the correct option is (a). Physics

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