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Question

The IP1′ IP2′ IP3′ IP4′ and IP5 of an element are 7.1,14.3,34.5,46.8,162.2 eV respectively. The element is likely to be:

A
Na
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B
Si
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C
F
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D
Ca
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Solution

The correct option is C Si
From given data, it can be seen that,
The difference of IP4andIP5 is maximum.
So its valency = 4.
Generally, group 14th has valency 4.
So group = IVA or 14th.
Thus, element belongs to Carbon family.
Among given options, Si belongs to carbon family so it must be Si.

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