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Question

The dissociation constant of two acids $$HA_1$$ and $$HA_2$$ are $$3.14\times 10^{-4}$$ and $$1.96\times 10^{-5}$$ respectively. The relative strength of the acid will be approximately:


A
1:4
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B
4:1
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C
1:16
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D
16:1
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Solution

The correct option is D $$4:1$$
$$\dfrac {\alpha_1}{\alpha_2}=\sqrt {\dfrac {K_{a_1}}{K_{a_2}}}=\sqrt {\dfrac {3.14\times 10^{-4}}{1.96\times 10^{-5}}}=4:1$$

Chemistry

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