Question

# The dissociation constant of two acids $$HA_1$$ and $$HA_2$$ are $$3.14\times 10^{-4}$$ and $$1.96\times 10^{-5}$$ respectively. The relative strength of the acid will be approximately:

A
1:4
B
4:1
C
1:16
D
16:1

Solution

## The correct option is D $$4:1$$$$\dfrac {\alpha_1}{\alpha_2}=\sqrt {\dfrac {K_{a_1}}{K_{a_2}}}=\sqrt {\dfrac {3.14\times 10^{-4}}{1.96\times 10^{-5}}}=4:1$$Chemistry

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