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Ostwald Dilution Law

The dissociat...

Question

The dissociation constants for $H C O O H$ and ${C H}_{3} C O O H$ are $2.1 \times 10^{- 4}$ a.nd $1.8 \times 10^{- 5}$ respectively. Calculate the relative strengths of the acids.

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Solution

The strength of an acid is directly proportional to square root of dissociation constants of acids. So relative strength of the given acids are
$\frac{(A c i d i c S t r e n g t h)_{H C O O H}}{(A c i d i c S t r e n g t h)_{C H_{2} C O O H}} = \frac{\sqrt{(D i s s o c i a t i o n c o n s t a n t)_{H C O O H}}}{\sqrt{(D i s s o c i a t i o n c o n s t a n t)_{C H_{2} C O O H}}}$
Relative Acidic Strength= $\frac{(A c i d i c S t r e n g t h)_{H C O O H}}{(A c i d i c S t r e n g t h)_{C H_{2} C O O H}} = \frac{\sqrt{2.1 \times 10^{- 4}}}{\sqrt{1.8 \times 10^{- 5}}} = 3.415$

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