The dissociation constants of two acids, HA1 and HA2, are 4.5×10−4 and 1.8×10−5 respectively. If both are having equal concentrations, then the relative strength of the acids is:
A
5:2
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B
2:5
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C
5:1
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D
1:5
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Solution
The correct option is B5:1 The dissociation of acid is given by the following equation: HA→H++A−
The given acids have a very low dissociation constant, i.e., the HA concentration can be assumed to be unchanged.
Therefore, [H+]=√Kac. Since, the concentration is assumed to be constant, the relative strength =H+HA1H+HA2=√451.8=5:1.