Question

# The distance between the lines 12x−5y+20=0 and 12x−5y−6=0 is

A
5 units
B
4 units
C
2 units
D
1 unit

Solution

## The correct option is C 2 unitsThe lines 12x−5y+20=0 and 12x−5y−6=0  are parallel. Hence the distance between them is, d=|c1−c2|√a2+b2 ∴d=|20+6|√(12)2+(−5)2=2613=2 units

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