Question

The distance between the lines $12x-5y+20=0$ and $12x-5y-6=0$ is

• A. $5\text{units}$
• B. $4\text{units}$
• C. $2\text{units}$
• D. $1\text{unit}$

Answer 1

The correct option is C $2\text{units}$

The lines $12x-5y+20=0$ and $12x-5y-6=0$ are parallel.
Hence the distance between them is,
$d=\frac{|c_1-c_2|}{\sqrt{a^2+b^2}}$
$\therefore d=\frac{|20+6|}{\sqrt{{\left(12\right)}^2+{(-5)}^2}}=\frac{26}{13}=2\text{units}$