The correct option is B 2√2 units
The distance between two points (x1,y1) and (x2,y2) is √(x2−x1)2+(y2−y1)2.
Replacing (5,5) for (x1,y1) and (3,3) for (x2,y2)
we get,
√(3−5)2+(3−5)2=√4+4=2√2 units
Hence, the distance between the points (5, 5) and (3, 3) is 2√2 units.