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Question

The distance between the points (5, 5) and (3, 3) is ___.

A
2 units
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B
22 units
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C
2 units
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D
82 units
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Solution

The correct option is B 22 units
The distance between two points (x1,y1) and (x2,y2) is (x2x1)2+(y2y1)2.

Replacing (5,5) for (x1,y1) and (3,3) for (x2,y2)
we get,
(35)2+(35)2=4+4=22 units

Hence, the distance between the points (5, 5) and (3, 3) is 22 units.

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