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Question

The distance between the points (5,9) and (11,y) is 10 units. Find the values of y.

A
2,17
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B
1,17
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C
1,27
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D
1,17
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Solution

The correct option is B 1,17
A(5,9) B(11,y)
AB=10
=10=(115)2+(y+9)2
squaring on both sides
100=(6)2+(y+9)2
100=36+(y+9)2
(y+9)2=64
y+9=8, y+9=8
y=1, y=17
y=1,17.

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