The distance between the top of two trees 20 m and 28 m high is 17 m. The horizontal distance between the trees is

11 m

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31 m

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15 m

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9 m

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Solution

The correct option is C
15 m

AB = (28 – 20 ) m = 8m

Applying Pythagoras theorem

${A B}^{2}$ + ${B E}^{2}$ = ${A E}^{2}$

64+ ${B E}^{2}$ = 289

BE = 15m

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