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Question

The distance of closest approach of an α- particle fired towards a nucleus with momentum p,is r. The distance of closest approach when the momentum of α-particle is 2p is

A
2r
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B
4r
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C
r/2
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D
r/4
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Solution

The correct option is B r/4
12mv2= q1 q24πϵ0 r

Initially, p22m=2e q4πϵ0 r ----(1)

Now, (2p)22m=2eq4πϵ0 r1 ----(II)

Equation (I)÷(ii)

14=r1r

r1=r4

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