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Question

The distance of the plane passing through (1, 1, 1) and perpendicular to the line  x13=y10=z14 from the origin is
  1. 34
  2. 45
  3. 75
  4. 0


Solution

The correct option is C 75
Equation of the plane is 3(x – 1) + 4(z – 1) = 0
3x+4z7=0
 Dist. from the origin =|7|32+42=75

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