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Question

The distance of the point (1,5,9) from the planexy+z=5 measured along a straight line x=y=z is

A
35
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B
103
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C
53
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D
310
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Solution

The correct option is B 103
P(1,5,9), Plane:xy+z5=0

Line: x1=y1=z1=r

From fig. (x1)=r

(y+5)=r

(z9)=r

x=r+1

y=r5

z=r+9

r+1r+5+r+95=0

r=10

(x,y,z)=(10+1,105,10+9)

(x,y,z)=(9,15,1)

distance(91)2+(15+5)2+(19)2=103

Ans:B

1045543_1032429_ans_e5e47fbc9a6c4d43b57e694c3996daca.png

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