The distance of the point (2,3) from the line 3x+3y=17, measured parallel to the line x−y=4 is
A
4√2
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B
5√2
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C
√2
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D
none of these
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Solution
The correct option is B√2 Coordinate of any point on the line through (2,3) and parallel to the line x−y=4, at a distance r, are (2+rcosθ,3+rsinθ), where tanθ=1. If this point lies on the line 3x+2y=17, then 3(2+rcosθ)+2(3+rsinθ)=17 ⇒6+3r.1√2+6+2r.1√2=17⇒5√2r=5 ⇒r=√2.