Question

The distance travelled by a body during last second of its upward journey is $d$, when the body is projected with certain velocity vertically up. If the velocity of projection is doubled, the distance travelled by the body during the last second of its total flight is

• A. $2d$
• B. $4d$
• C. $d/2$
• D. $d$

Answer 1

The correct option is A $2d$

Let the total time of flight in first$.$

Case in $t$$,$

After reaching the height point particle will have velocity equal to zero and will take time $\frac{t}{2}$ to come to the ground$.$

now $t=\frac{2u}{g}$

So time to come down from peak $t=\frac{u}{g}$

Hence,

option $\left(A\right)$ is correct answer.