Question

The distances covered by a particle thrown in a vertical plane, in horizontal and vertical directions at any instant of time 't' are x $=$ 3t and $y=4t-5t^2$.The acceleration due to gravity is

• A. $8m/s^2$
• B. $9m/s^2$
• C. $10m/s^2$
• D. $16m/s^2$

Answer 1

Answer: (C)

$10m/s^2$

Range, $x=3t$
vertical height, $y=4t-5t^2=4t-\frac{1}{2}\left(10\right)t^2$

equivalent formula, $s=ut+\frac{1}{2}g{t}^2$
$\therefore g=10m/s^2$