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Question

The driver of a train traveling at 40 ms1 applies the brakes as the train enters a station. The train slows down at a rate of 2 ms2. The distance traveled by train before stopping is


A
200 m
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B
300 m
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C
400 m
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D
500 m
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Solution

The correct option is C 400 m

Given, the initial speed u=40 ms1, acceleration a=2 ms2 (Retardation as it is negative), final velocity v=0 and distance traveled by train before stopping is s

Using equation of motion,

v2=u2+2as

02=402+2×2×s

On solving s=400 m


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