The E for O Cl - - Cl - and Cl - - 1 2 Cl 2 are 0-94V and -1-36V- E for OCl - - 1 2 Cl 2 is-

The correct option is C 0.52V OCl ^ +2 e ^ → Cl ^ #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; ...

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Byju's Answer

Standard VIII

Chemistry

Surface Tension

The E for ...

Question

The $E$ for $O {C l}^{-} | {C l}^{-}$ and ${C l}^{-} | \frac{1}{2} {C l}_{2}$ are $0.94 V$ and $- 1.36 V . E$ for ${O C l}^{-} | \frac{1}{2} {C l}_{2}$ is:

- 0.42 V

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- 2.20 V

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0.52 V

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1.04 V

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Solution

The correct option is C $0.52 V$
${O C l}^{-} + 2 e^{-} \to {C l}^{-}$ $E_{{O C l}^{-} / {C l}^{-}}^{0} = 0.94 V . . . . . . . . (1)$
${C l}^{-} \to \frac{1}{2} {C l}_{2} + e^{-}$ $E_{{C l}^{-} / \frac{1}{2} {C l}_{2}}^{0} = - 1.36 V . . . . . . (2)$
${O C l}^{-} + e^{-} \to \frac{1}{2} {C l}_{2}$ $E_{{O C l}^{-} / \frac{1}{2} {C l}_{2}}^{0} = ? . . . . . . . . . (3)$
$△ G_{3}^{0} = △ G_{1}^{0} + △ G_{2}^{0} - 1 \times F \times E_{3}^{0} = - 2 \times F \times 0.94 - 1 \times F \times (- 1.36) E_{3} = 2 \times 0.94 - 1.36 = 0.52 V$

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Similar questions

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The E for OCl−|Cl− and Cl−|12Cl2 are 0.94V and −1.36V.E for OCl−|12Cl2 is:

The correct option is C 0.52VOCl−+2e−→Cl− E0OCl−/Cl−=0.94V........(1)Cl−→12Cl2+e− E0Cl−/12Cl2=−1.36V......(2)OCl−+e−→12Cl2 E0OCl−/12Cl2=?.........(3)△G03=△G01+△G02−1×F×E03=−2×F×0.94−1×F×(−1.36)E3=2×0.94−1.36=0.52V

The $E$ for $O {C l}^{-} | {C l}^{-}$ and ${C l}^{-} | \frac{1}{2} {C l}_{2}$ are $0.94 V$ and $- 1.36 V . E$ for ${O C l}^{-} | \frac{1}{2} {C l}_{2}$ is: