Question

# The $${ E }^{ }$$ for $$O{ Cl }^{ - }|{ Cl }^{ - }$$ and $${ Cl }^{ - }|\cfrac { 1 }{ 2 } { Cl }_{ 2 }$$ are $$0.94V$$ and $$-1.36V.{ E }^{ }$$ for $${ OCl }^{ - }|\cfrac { 1 }{ 2 } { Cl }_{ 2 }$$ is:

A
0.42V
B
2.20V
C
0.52V
D
1.04V

Solution

## The correct option is C $$0.52V$$$${ OCl }^{ - }+2{ e }^{ - }\rightarrow { Cl }^{ - }$$                                                    $${ E }_{ { { OCl }^{ - } }/{ { Cl }^{ - } } }^{ 0 }=0.94V........(1)$$$${ Cl }^{ - }\rightarrow \cfrac { 1 }{ 2 } { Cl }_{ 2 }+{ e }^{ - }$$                                                     $${ E }_{ { { Cl }^{ - } }/\cfrac{ 1 }{ 2 } { { Cl }_{ 2 } } }^{ 0 }=-1.36V......(2)$$$${ OCl }^{ - }+{ e }^{ - }\rightarrow \cfrac { 1 }{ 2 } { Cl }_{ 2 }$$                                                 $${ E }_{ { { OCl }^{ - } }/\cfrac { 1 }{ 2 } { { Cl }_{ 2 } } }^{ 0 }=?.........(3)$$$$\triangle { G }_{ 3 }^{ 0 }=\triangle { G }_{ 1 }^{ 0 }+\triangle { G }_{ 2 }^{ 0 }\\ -1\times F\times { E }_{ 3 }^{ 0 }=-2\times F\times 0.94-1\times F\times \left( -1.36 \right) \\ { E }_{ 3 }=2\times 0.94-1.36=0.52V$$Chemistry

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