The earth receives solar radiation at a rate of $8.2 J c m^{- 2} m i n^{- 1}$ . If the sun radiates as the black bodies, the temperature at the surface of the sun will be (the angle subtended by sun on the earth in suppose ${0.53}^{\circ}$ and Stefan constant is $σ = 5.67 \times 10^{- 8} W m^{- 2} k^{4}$ )

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Solution

Earth movement radiation at rate of $8.2 J c m^{- 2} m i n^{- 1}$
Since angle subtended at earth surface is 0.53 so total energy radiation by sun will be
$\frac{360}{0.53} \times 8.2 J c m^{- 2} m i n^{- 1} = \frac{360}{0.53} \times \frac{8.2 J c m^{- 2} m i n^{- 1}}{60 s} = \frac{360}{0.53} \times 8.2 \times 20 J m^{- 2} s^{- 1} = 9.28 \times 10^{5} J m^{- 2} s^{- 1}$
Now,
$\frac{q}{A} = σ T^{4} \frac{9.28 \times 0^{3}}{567 \times 10^{- 8}} = T^{4} T ≃ 2011 K$

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Q. The earth receives solar radiation, at a rate of

8.2 {J cm}^{- 2} {min}^{- 1}

. Assuming that the sun radiates like a blackbody, calculate the surface temperature of the sun. The angle subtended by the sun on the earth is

{0.53}^{\circ}

and the Stefan's constant

σ = 5.67 \times 10^{- 8}

{Wm}^{- 2} K^{- 4}

The earth receives solar radiation at a rate of 8.2 J/ $c m^{2}$ - minute. Assuming that the sun radiates like a blackbody, calculate the surface temperature of the sun. The angle subtended by the sun on the earth is 0.53 $^{\circ}$ and the Stefan constant $σ = 5.67 \times 10^{- 8} W / m^{2}$ - K4.