The earth's gravitational force causes an acceleration of 5 $m s^{- 2}$ in a 1 kg mass somewhere in space. How much will the acceleration of a 3 kg mass be at the same place?

9.8 $m s^{- 2}$

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10 $m s^{- 2}$

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5 $m s^{- 2}$

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Solution

The correct option is D. 5 $m s^{- 2}$ .
The acceleration produced by the gravitational force of earth does not depend on the mass of the object. So, the acceleration produced in the 3 kg mass will be the same as that produced in 1 kg mass i.e. 5 $m s^{- 2}$ .
$a c c e l e r a t i o n d u e t o g r a v i t y a t s o m e h e i g h t a b o v e t h e s u r f a c e o f t h e e a r t h,$
$g^{'} = \frac{g}{{(1 + \frac{h}{R})}^{2}}$

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The earth's gravitational force causes an acceleration of 5 ms−2 in a 1 kg mass somewhere in space. How much will the acceleration of a 3 kg mass be at the same place?

The earth's gravitational force causes an acceleration of 5 $m s^{- 2}$ in a 1 kg mass somewhere in space. How much will the acceleration of a 3 kg mass be at the same place?