Question

# The eccentricity of the ellipse 12x2+7y2=84 is equal to √57 √512 √512 √57

Solution

## The correct option is B √512 12x2+7y2=84x27+y212=1a2=7; b2=12Focal length, c=√b2−a2c=√12−7=√5e=ca=√512

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