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Question

The eccentricity of the ellipse 25x2+16y2=400 is

A
3/5
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B
1/3

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C
2/5

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D
1/5
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Solution

The correct option is A 3/5

25x2+16y2=400
x216+fracy225=1 ...(1)
Comparing equation (1) is x2a2+y2b2=1, we get:
a2=16 and b2=25
Here, a<b, so the major and the minor axes of the ellipse are along the x-axis and y-axis, respectively.
Now, e=1b2a2
e=11625
e=925
e=35

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