Question

The electric field in a region is given by →E=35E0→i+45E0^j with E0=2.0×103NC−1. Find the flux of this field through a rectangular surface of area 0.2 m2 parallel to the y−z plane.

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Solution

Mg−T=DT=mgf=mgT=NN=mgϕ=→E⋅^nds→E=3/4E0i+4/5E0^iRectangle in yz planeSo Area vector along ^iϕ=(3/5E0^i+4/5E0^j)⋅(0.2)^i35×E0×0.2=35×2×103×0.2=0.6×0.4×103=240 Nm2c−1m.

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