The electric field in a region of space is given by E-5-2- Nc-1 - The electric flux due to this field through an area 2m2 lying in the Y-Z plane in S-I- units is

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Question

The electric field in a region of space is given by $\to E = (^5 i +^2 j) N c^{- 1}$ . The electric flux due to this field through an area $2 m^{2}$ lying in the Y-Z plane in S.I. units is

10

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20

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10 \sqrt{2}

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2 \sqrt{29}

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Solution

The correct option is B $10$
As $2 m^{2}$ area is in y-z plane its area vector which is perpendicular to y-z plane is in x axis.
$∴$ area vector $= 2 (^i)$
given $E = 5 i + 2 j$
We know flux $ϕ = E . A$
$= (2 i) . (5 i + 2 j)$
$ϕ = 10$

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The electric field in a region of space is given by →E=(^5i+^2j)Nc−1 . The electric flux due to this field through an area 2m2 lying in the Y-Z plane in S.I. units is

The correct option is B 10As 2m2 area is in y-z plane its area vector which is perpendicular to y-z plane is in x axis.∴ area vector =2(^i)given E=5i+2jWe know flux ϕ=E.A=(2i).(5i+2j)ϕ=10

The electric field in a region of space is given by $\to E = (^5 i +^2 j) N c^{- 1}$ . The electric flux due to this field through an area $2 m^{2}$ lying in the Y-Z plane in S.I. units is

The correct option is B $10$
As $2 m^{2}$ area is in y-z plane its area vector which is perpendicular to y-z plane is in x axis.
$∴$ area vector $= 2 (^i)$
given $E = 5 i + 2 j$
We know flux $ϕ = E . A$
$= (2 i) . (5 i + 2 j)$
$ϕ = 10$