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Question

The electric field intensity at a point near and outside the surface of a charged conductor of any shape is '$${ E }_{ 1 }$$'. The electric field intensity due to uniformly charged infinite thin plane sheet is '$${ E }_{ 2 }$$'. The relation between '$${ E }_{ 1 }$$' and '$${ E }_{ 2 }$$' is :


A
2E1=E2
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B
E1=E2
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C
E1=2E2
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D
E1=4E2
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Solution

The correct option is C $${ E }_{ 1 }=2{ E }_{ 2 }$$
Electric field outside the conductor $$E_1 = \dfrac{\sigma}{\epsilon_o}$$
Electric field due to uniformly charged infinitely thin plate  $$E_2 = \dfrac{\sigma}{2\epsilon_o}$$
$$\implies$$ $$E_1 = 2E_2$$

Physics

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