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Question

The electric field maintained inside a conductor is 10N/C and they drift with a speed of 5×104m/s
What is the relaxation time for the electrons?


A
5me×105  seconds where m is the mass of the electrons and e is the charge
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B
5em×105  seconds where m is the mass of the electrons and e is the charge
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C
me×104  seconds where m is the mass of the electrons and e is the charge
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D
5me×104 seconds where m is the mass of the electrons and e is the charge
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Solution

The correct option is A 5me×105  seconds where m is the mass of the electrons and e is the charge
From the videos you would have seen that,
Vd=eEτm, where τ =Average time between successive collisions also called relaxation time.
Now you just need to plug in the values.
5×104=10eτ/m
τ=5me×105seconds.
You can use dimensional analysis to eliminate some options. Sometimes this method can be very useful.



 

Physics

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