Question

The electric flux $$\phi$$ through a hemispherical surface of radius R, placed in a uniform electric field of intensity E parallel to the axis of its circular plane is :

A
(4/3)πR3E
B
2πR2E
C
πR2E
D
2πRE

Solution

The correct option is D $$\pi R^2 E$$As the field intensity E is parallel to axis of circular plane so only this circular surface will contribute the flux through the hemisphere. By Gauss's law, flux , $$\phi=\int E.ds=E.\pi R^2$$Physics

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