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Question

The electric motor operates on 200V supply and a current of 15 A. If the efficiency of motor is 40% then resistance of motor winding is

A
10 Ω
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B
8 Ω
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C
20 Ω
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D
25 Ω
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Solution

The correct option is C 8 Ω
input power P=VI=20015=3000
power dissipated as heat I2R=225R
Efficiency=output powerinput power
40100=3000225R3000
820=3000225R3000
24000=600004500R4500R=36000R=360004500R=8Ω

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