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Question

The electric potential $$V$$ at any point $$\left(x,  y,  z\right)$$, all in meters, in space in given by $$V = 4{x}^{2}  volt$$. The electric field at the point $$\left(1,  0,  2\right)$$ in $${volt}/{meter}$$ is :


A
8 along positive X-axis
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B
16 along negative X-axis
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C
16 along positive X-axis
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D
8 along negative X-axis
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Solution

The correct option is B 8 along negative X-axis
$$\vec { E } = -\displaystyle\frac { dV }{ dx } \hat { i } $$
    $$= -8x \hat { i }    { volt }/{ meter }$$
$${ \vec { E }  }_{ \left( 1,0,2 \right)  } = -8 \hat { i }   { V }/{ m }$$.

Physics
NCERT
Standard XII

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