The electron affinity and ionization potential of iodine are $3.43 e V$ and $10. 5 e V$ respectively. The electronegativity of iodine in Pauling scale is:
(correct answer +2, wrong answer -0.5)

3.48

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2.48

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1.5

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2.2

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Solution

The correct option is B $2.48$
We know that,
Electronegativity can be calculated using Mulliken's formula,

$Electronegativity = \frac{Ionization energy + electron affinity}{2}$
$= \frac{3.43 + 10.5}{2} = 6.96$

Mulliken's scale is 2.8 times the Pauling scale.
Hence, Pauling electronegativity $\Rightarrow \frac{6.96}{2.8} = 2.48$

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The electron affinity and ionization potential of iodine are 3.43 eV and 10.5 eV respectively. The electronegativity of iodine in Pauling scale is: (correct answer +2, wrong answer -0.5)

The correct option is B 2.48We know that, Electronegativity can be calculated using Mulliken's formula, Electronegativity =Ionization energy + electron affinity2 =3.43+10.52=6.96 Mulliken's scale is 2.8 times the Pauling scale. Hence, Pauling electronegativity ⇒6.962.8=2.48

The electron affinity and ionization potential of iodine are $3.43 e V$ and $10. 5 e V$ respectively. The electronegativity of iodine in Pauling scale is:
(correct answer +2, wrong answer -0.5)