The electronic configuration ${1 s}^{2} {2 s}^{2} {2 p x}^{1} {2 p y}^{1} {2 p z}^{1}$ is of:

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Solution

The correct option is A N
Total electrons = 7 = (Atomic number). Therefore, its nitrogen.

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Nitrogen has the electronic configuration $1 s^{2}, 2 s^{2} 2 p_{x}^{1} 2 p_{y}^{1} 2 p_{z}^{1}$ and not $1 s^{2}, 2 s^{2} 2 p_{x}^{2} 2 p_{y}^{1} 2 p_{z}^{0}$ which is determined by

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is:

The element whose electronic configuration is $1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}$ is a/an?

Q. Match the electronic configurations of the elements given in List - I with their correct characteristic(s) (i.e., properties for given configuration) given in List - II.

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The electronic configuration 1s22s22px12py12pz1 is of:

The correct option is A NTotal electrons = 7 = (Atomic number). Therefore, its nitrogen.

The electronic configuration ${1 s}^{2} {2 s}^{2} {2 p x}^{1} {2 p y}^{1} {2 p z}^{1}$ is of:

The correct option is A N
Total electrons = 7 = (Atomic number). Therefore, its nitrogen.