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Question

The electrostatic force of repulsion between two equal positively charged ions is 51.84×109N, when they are separated by a distance of 0.4 nm. How many electrons are missing from each ion?

A
6
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B
5
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C
7
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D
3
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Solution

The correct option is A 6
q1=q2=q(say)

r=0.4nm=4×1010m

F=51.84×109N

F=q1q24πϵor2

9×109×q216×1020=51.84×109

q2=16×5.76×1038

q=4×2.4×1019C

N=number of electrons

q=NeN=qe

N=4×2.4×10191.6×1019

N=6

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