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Question

The emf of the three galvanic cells:
(i) Zn|Zn2+ (1 M)||Cu2+ (1 M)|Cu
(ii) Zn|Zn2+ (0.1 M)||Cu2+ (1 M)|Cu
(iii) Zn|Zn2+ (1 M)||Cu2+ (0.1 M)|Cu
are represented by E1, E2 and E3 respectively. Which of the following is true?

A
E1>E2>E3
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B
E3>E2>E1
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C
E3>E1>E2
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D
E2>E1>E3
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Solution

The correct option is D E2>E1>E3
Zn+Cu2+Zn2++Cu
Ecell=EcellRTnF ln [Zn+2][Cu+2]

So higher the value of [Zn+2][Cu+2], lower will be the value of Ecell.

(i) [Zn+2][Cu+2]=1

(ii) [Zn+2][Cu+2]=0.11=0.1

(iii) [Zn+2][Cu+2]=10.1=10


E2>E1>E3

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