Question

# The ends of a metal rod are kept at temperature $$\theta_1$$ and $$\theta_2$$ with $$\theta_2 > \theta_1$$. Then rate of flow of heat along the rod is directly proportional to

A
the length of the rod
B
the diameter of the rod
C
the cross-sectional area of the rod
D
the temperature difference (θ2θ1) between the ends of the rod

Solution

## The correct options are B the cross-sectional area of the rod D the temperature difference $$(\theta_2 - \theta_1)$$ between the ends of the rodThe rate of heat flow is directly proportional to cross-sectional area of rod, and the temperature difference between the ends of the rod. It is inversely proportional to length of rod and directly proportional to square of diameter.The rate of flow of heat is given by$$P=\dfrac {Q} {t} = \dfrac {KA (\theta_2 - \theta_1)} {l}$$Where $$K$$ is the thermal conductivity, $$A$$ is the cross-sectional area and l the length of the rod. Hence, the correct choice are $$(c)$$ and $$(d).$$Physics

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