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Question

The energies $$E_1 \ and\  E_2$$ of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths i.e. $$\lambda_1 \ and \ \lambda_2$$ will be:


A
λ1=λ2
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B
λ1=2λ2
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C
λ1=4λ2
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D
λ1=12λ2
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Solution

The correct option is A $$\lambda_{1} =2\lambda _{2}$$
Given the value of $$E_1 = 25 eV\  and\   E_2 = 50 eV$$
$$E_1 = \dfrac {hc}{\lambda_1}, E_2 = \dfrac {hc}{\lambda_2}$$
By divide $$E_1$$ and $$E_2$$

$$\Rightarrow \dfrac {25}{50} = \dfrac {\lambda_2}{\lambda_1}$$
$$\lambda_1 = 2\lambda_2$$

So, the correct option is $$B$$

Chemistry

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