Question

# The energies $$E_1 \ and\ E_2$$ of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths i.e. $$\lambda_1 \ and \ \lambda_2$$ will be:

A
λ1=λ2
B
λ1=2λ2
C
λ1=4λ2
D
λ1=12λ2

Solution

## The correct option is A $$\lambda_{1} =2\lambda _{2}$$Given the value of $$E_1 = 25 eV\ and\ E_2 = 50 eV$$$$E_1 = \dfrac {hc}{\lambda_1}, E_2 = \dfrac {hc}{\lambda_2}$$By divide $$E_1$$ and $$E_2$$$$\Rightarrow \dfrac {25}{50} = \dfrac {\lambda_2}{\lambda_1}$$$$\lambda_1 = 2\lambda_2$$So, the correct option is $$B$$Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More