Question

The energies $E_{1}and{E}_2$ of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths i.e. ${\lambda }_{1}and{\lambda }_2$ will be:

• A. ${\lambda }_1={\lambda }_2$
• B. ${\lambda }_1=2{\lambda }_2$
• C. ${\lambda }_1=4{\lambda }_2$
• D. ${\lambda }_1=\frac{1}{2}{\lambda }_2$

Answer 1

Answer: (B)

${\lambda }_1=2{\lambda }_2$

Given the value of $E_1=25eVand{E}_2=50eV$

$E_1=\frac{hc}{{\lambda }_1},E_2=\frac{hc}{{\lambda }_2}$

By divide $E_1$ and $E_2$

$\Rightarrow \frac{25}{50}=\frac{{\lambda }_2}{{\lambda }_1}$

${\lambda }_1=2{\lambda }_2$

So, the correct option is $B$