The energy of a photon corresponding to the visible light of maximum wavelength is approximately

1 eV

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1.6 eV

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3.2 eV

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7 eV

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Solution

The correct option is B 1.6 eV
$M a x i m u m w a v e l e n g t h o f r e d l i g h t = 750 n m = 750 \times 10^{- 9} m E n e r g y, E = \frac{h c}{λ} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{750 \times 10^{- 9}} \times \frac{1}{1.6 \times 10^{- 9}} = 1.6 e V$

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The energy of a photon corresponding to the visible light of maximum wavelength is approximately

The correct option is B 1.6 eVMaximumwavelengthofredlight=750nm=750×10−9mEnergy,E=hcλ=6.6×10−34×3×108750×10−9×11.6×10−9=1.6eV

The correct option is B 1.6 eV
$M a x i m u m w a v e l e n g t h o f r e d l i g h t = 750 n m = 750 \times 10^{- 9} m E n e r g y, E = \frac{h c}{λ} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{750 \times 10^{- 9}} \times \frac{1}{1.6 \times 10^{- 9}} = 1.6 e V$