Question

The energy of the second Bohr orbit in the hydrogen atom is $-3.41eV.$ The energy of the second Bohr orbit of $H{e}^{+}$ ion would be:

• A. $-0.85eV$
• B. $-13.64eV$
• C. $-1.70eV$
• D. $-6.82eV$

Answer 1

Answer: (B)

$-13.64eV$

The energy of electron in Bohr's model is directly proportional to $\frac{Z^2}{n^2}$.

Therefore the energy of electron in $2nd$ orbit of $H{e}^{+}$ is 4 times the energy of electron in $2nd$ orbit of Hydrogen.

Note: Bohr's model can be applied to single electrons system only.

Hence option B is correct